SOLUTION: An integer is seven more than another integer. Twice the larger integer is one less than the square of the smaller integer. Find the two integers.
Question 366355: An integer is seven more than another integer. Twice the larger integer is one less than the square of the smaller integer. Find the two integers. Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! let one integer be x
the other is x+7
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twice the larger = 2(x+7)
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1 less than square of the smaller
x^2-1
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x^2-1=2(x+7)
x^2-1=2x+14
x^2-2x-1-14=0
x^2-2x-15=0
x^2-5x+3x-15=0
x(x-5)+3(x-5)=0
(x-5)(x+3)=0
x=5 OR x= -3
the integers are 5, 12
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m.ananth@hotmail.ca
