SOLUTION: how many liters of a 10% alcohol solution must be mixed with 90 liters of a 50% solution to get a 20% solution

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: how many liters of a 10% alcohol solution must be mixed with 90 liters of a 50% solution to get a 20% solution      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 366057: how many liters of a 10% alcohol solution must be mixed with 90 liters of a 50% solution to get a 20% solution
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Let A be the amount of 10% alcohol solution.
10A%2B50%2890%29=20%28A%2B90%29
10A%2B4500=20A%2B1800
A%2B450=2A%2B180
highlight%28A=270%29 liters.