| 
 
 
| Question 366047:   If a stone is tossed from the top of a 230 meter building, the height of the stone as a function of time is given by h(t) = -9.8t2 – 10t + 230, where t is in seconds, and height is in meters. After how many seconds will the stone hit the ground? Round to the nearest hundredth’s place; include units in your answer.
 Answer by Alan3354(69443)
      (Show Source): 
You can put this solution on YOUR website! It hits the ground when h(t) = 0. Solve the equation for t.
 ----------------
 h(t) = -9.8t2 – 10t + 230 = 0
 ------------------
 If this happens on Earth, it should be h(t) = -4.9t^2 – 10t + 230, not 9.8t^2
 ------------------
 Using 9.8:
 
 
 | Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc) |  | Quadratic equation  (in our case  ) has the following solutons: 
 
  
 For these solutions to exist, the discriminant
  should not be a negative number. 
 First, we need to compute the discriminant
  :  . 
 Discriminant d=9116 is greater than zero. That means that there are two solutions:
  . 
 
  
  
 Quadratic expression
  can be factored: 
  Again, the answer is: -5.38151765807347, 4.36110949480817.
Here's your graph:
 
  |  ------------
 Using 4.9:
 
 
 | Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc) |  | Quadratic equation  (in our case  ) has the following solutons: 
 
  
 For these solutions to exist, the discriminant
  should not be a negative number. 
 First, we need to compute the discriminant
  :  . 
 Discriminant d=4608 is greater than zero. That means that there are two solutions:
  . 
 
  
  
 Quadratic expression
  can be factored: 
  Again, the answer is: -7.94716846876618, 5.90635214223557.
Here's your graph:
 
  |  --------------
 Ignore the negative values.
 t = x in seconds
 
 | 
  
 | 
 |