SOLUTION: Solve f(x) = (x^3) - (6x^2) + 7x + 2 = 0

Hi, 

Note: exploring factor of the constant term 2, found that x = 2 is a root

f(2) = 8 - 24 + 14 + 2 = 0

        x^2 - 4x -1

        __________________________

x - 2 | x^3 -  6x^2  + 7x   +  2

      - (x^3 - 2x^2

       ---------------

                -4x^2 + 7x

             - (-4x^2 + 8x )

                ---------                      

                         -x  + 2 

                      - (-x  + 2)

                          --------

                                 0

    

  x^2 - 4x -1