SOLUTION: find 2 consecutive integers whose product is 5 less than 5 times their sum

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Question 365343: find 2 consecutive integers whose product is 5 less than 5 times their sum
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
x(x+1) = 5 (x+x+1)-5,
x%5E2+%2B+x+=+10x%2B5+-+5,
x%5E2-9x+=+0,
x(x-9) = 0, or x = 0 or x = 9.
So we get two sets of answers: {0,1} or {9,10}.