SOLUTION: What is the solution for x? (All logarithms have the base "b") Logx = Log2^3 + Log25^.5 - Log20

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Question 364990: What is the solution for x?
(All logarithms have the base "b")
Logx = Log2^3 + Log25^.5 - Log20

Found 2 solutions by Alan3354, nerdybill:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
What is the solution for x?
(All logarithms have the base "b")
Logx = Log2^3 + Log25^.5 - Log20
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log(x) = log(8) + log(5) - log(20)
log(x) = log(8*5/20)
log(x) = log(2)
x = 2

Answer by nerdybill(7384) About Me  (Show Source):