You can put this solution on YOUR website! Vertex form of a parabola: y = a(x - h)^2 + k
Convert y = -3x^2 + 6x to vertex form of a parabola.
y = -3 (x^2 - 2x)
Completing the square
y = -3 (x^2 -2x + 1)- 1 + 3
y = -3 (x - 1)^2 + 2
a = -3
h = 1
k = 2
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Vertex: (1,2)
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x-int.: y = 0 => 0 = -3x^2 + 6x
3x^2 = 6x
3x = 6
x = 2
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y-int.: x = 0 => y = y = -3(0)^2 + 6(0)
y = 0
The vertex is at (1,2). The x-intercept is 2 while the y-intercept is 0.
