SOLUTION: A runner decides to run out in the country. He begins to run at an average rate of 9 miles per hour. He runs a certain distance and then turns around and returns along the same r
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Question 364834: A runner decides to run out in the country. He begins to run at an average rate of 9 miles per hour. He runs a certain distance and then turns around and returns along the same route at an average rate of 6 miles per hour. If the round trip took two and a half hours, how far did the runner travel before turning around? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! A runner decides to run out in the country.
He begins to run at an average rate of 9 miles per hour.
He runs a certain distance and then turns around and returns along the same
route at an average rate of 6 miles per hour.
If the round trip took two and a half hours, how far did the runner travel
before turning around?
:
Let d = one-way distance (point of turning around)
:
Write a time equation: Time = dist/speed
:
outbound time + return time = 2.5 hrs + = 2.5
Multiply by 18 to clear the denominators, results:
2d + 3d = 18(2.5)
5d = 45
d =
d = 9 miles out in the country before turning around.
:
:
See if that's true + =
1 + 1.5 = 2.5
