SOLUTION: in a certain fraction, the denominator is 6 more than the numerator. if 3 is added to both the numerator and the denominator, the resulting fraction is equivalent to 5/7. what was

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Question 364627: in a certain fraction, the denominator is 6 more than the numerator. if 3 is added to both the numerator and the denominator, the resulting fraction is equivalent to 5/7. what was the original fraction(not in lowest terms)? ANSWER:12/18 I need help solving Thanks
Found 2 solutions by Fombitz, ewatrrr:
Answer by Fombitz(32388) About Me  (Show Source):
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi, 

Let x represent the numerator, then (x+6) would be the denominator

question states

%28%28x+%2B+3%29%2F%28x%2B3%2B3%29%29+=+%285%2F7%29

%28%28x+%2B+3%29%2F%28x%2B6%29%29+=+%285%2F7%29

cross multiply to solve for x

7(x+3) = 5(x+6) 

7x + 21 = 5x + 30

2x = 9

x = 9/2

checking our answer

%28%2815%2F2%29%2F%2821%2F2%29%29+=+15%2F21+=+5%2F7