SOLUTION: Solve the equation: 4x^2+4=x Answer choices: A.) 1 +- sqrt(63) B.) 1 +- i sqrt(63) divided by 8 C.) 1 +- i sqrt(63) divided by 4 D.) -1/4, 1/4 Thank you!

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Solve the equation: 4x^2+4=x Answer choices: A.) 1 +- sqrt(63) B.) 1 +- i sqrt(63) divided by 8 C.) 1 +- i sqrt(63) divided by 4 D.) -1/4, 1/4 Thank you!      Log On


   

Question 364599: Solve the equation: 4x^2+4=x
Answer choices:
A.) 1 +- sqrt(63)
B.) 1 +- i sqrt(63) divided by 8
C.) 1 +- i sqrt(63) divided by 4
D.) -1/4, 1/4
Thank you!
Answer by unlockmath(1688) About Me  (Show Source):
You can put this solution on YOUR website!
Hello,
With this 4x^2+4=x we want to subtract x from both sides to get:
4x^2-x+4=0
Now use quadratic Formula:
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
Plug in the values:
x+=+%28%2B1+%2B-+sqrt%28+1-4%2A4%2A4+%29%29%2F%282%2A4%29+
This gives us:
1+-sqrt-63/8
(1+-isqrt63)/8
There we go.
Make sense?
RJ
www.math-unlock.com