Question 364460: a father is twice as old as his son,fourteen years ago he was four times as old as his son, what is the age of the father and the son? Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! a father is twice as old as his son,fourteen years ago he was four times as old as his son, what is the age of the father and the son?
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son's age = x
father's age =2x
14 years ago
son was x-14 years
father was 2x-14 years
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2x-14 = 4(x-14)
2x-14 = 4x-56
-2x=-42
/2
x= 21 years son's age
Father's age = 2x=42 years
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m.ananth@hotmail.ca
