SOLUTION: When a ball is thrown, its height in feet h after t seconds is given by the equation h=vt-16t^2 where v is the initial upwards velocity in feet per second. If v=34 feet per

Algebra ->  Expressions-with-variables -> SOLUTION: When a ball is thrown, its height in feet h after t seconds is given by the equation h=vt-16t^2 where v is the initial upwards velocity in feet per second. If v=34 feet per       Log On


   



Question 364448: When a ball is thrown, its height in feet h after t seconds is given by the equation
h=vt-16t^2

where v is the initial upwards velocity in feet per second. If v=34 feet per second, find all values of t for which h=17 feet. Do not round any intermediate steps. Round your answer to decimal places.

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
h=vt-16t%5E2
+17=34t-16t%5E2
+16t%5E2-34t%2B17=0
Use the quadratic formula,
t+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
t+=+%2834+%2B-+sqrt%28+%28-34%29%5E2-4%2A16%2A17+%29%29%2F%282%2A16%29+
t+=+%2834+%2B-+sqrt%28+1156-1088%29%29%2F%2832%29+
t+=+%2834+%2B-+sqrt%28+68%29%29%2F%2832%29+
t+=+%2834+%2B-+2%2Asqrt%28+17%29%29%2F%2832%29+
highlight%28t+=+%2817+%2B-+sqrt%28+17%29%29%2F%2816%29%29+