SOLUTION: Find all of the real solutions of the polynomial equation. x^5 - x^4 -3x^3 + 5x^2 -2x = 0 So far I have gotten that I would need to take out an x x(x^4 - x^3 -3x^2 +5x -

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Find all of the real solutions of the polynomial equation. x^5 - x^4 -3x^3 + 5x^2 -2x = 0 So far I have gotten that I would need to take out an x x(x^4 - x^3 -3x^2 +5x -      Log On


   

Question 364381: Find all of the real solutions of the polynomial equation.
x^5 - x^4 -3x^3 + 5x^2 -2x = 0

So far I have gotten that I would need to take out an x
x(x^4 - x^3 -3x^2 +5x -2)
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
Factoring out x would give x%28x%5E4+-+x%5E3+-3x%5E2+%2B+5x+-2%29+=+0.
Now x%5E4+-+x%5E3+-3x%5E2+%2B+5x+-2+=+%28x-1%29%5E3%28x%2B2%29, so that the polynomial equation isx%28x-1%29%5E3%28x%2B2%29+=+0. The roots are 0, -2, or 1 (multiplicity 3).