SOLUTION: Please help me solve this I am lost. Solve the systems of equations by graphing. Then classify the system. {{{6x-y=36}}} {{{6x+7=-12}}} I am having a problem with this, Tha

Algebra ->  Graphs -> SOLUTION: Please help me solve this I am lost. Solve the systems of equations by graphing. Then classify the system. {{{6x-y=36}}} {{{6x+7=-12}}} I am having a problem with this, Tha      Log On


   



Question 364241: Please help me solve this I am lost.
Solve the systems of equations by graphing. Then classify the system.
6x-y=36
6x%2B7=-12
I am having a problem with this, Thanks

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Solve the systems of equations by graphing. Then classify the system.
6x-y=36
6x%2By=-12
:
You want to plot each equation on a graph, in order to do this it has to be
in the form; y = mx + b
:
Equation 1
6x - y = 36
Subtract 6x from both sides
-y = -6x + 36
y has to be positive, multiply by -1, this changes all the signs
y = 6x - 36
To plot this equation, substitute values for x, find y, a table like this
x | y
------
-1 |-42
0 |-36
+6 | 0
+10|+24
:
Since it is a linear equation you actually only need two coordinates
Should look like this
+graph%28+300%2C+200%2C+-6%2C+10%2C+-50%2C+40%2C+6x-36%29+
:
do the same with equation 2
6x + y = -12
Subtract 6x from both sides
y = -6x - 12
:
To plot this equation, substitute values for x, find y, a table like this
x | y
------
-3 |+6
0 |-12
+1 |-18
+4||-36
:
Plot both equations on the same graph, note the intersect at x=2, y=-24
This is the solution to this system of equations
:
Should look like this
+graph%28+300%2C+200%2C+-6%2C+10%2C+-50%2C+40%2C+6x-36%2C+-6x-12%29+
;
This is classified as, "an independent system of equations" (one solution)
:
You can prove this to yourself, substitute 2 for x and -24 for y and see
that both original equations are true.
:
Did this help you find your way in this?? Any questions?