Question 36423: solve: 7^3x-5=5^1+4x
Answer by fractalier(6550)   (Show Source):
You can put this solution on YOUR website! From 7^(3x-5) = 5^(1+4x)
take the log of both sides, then apply the power rule...
log[7^(3x-5)] = log[5^(1+4x)]
(3x-5)log7 = (4x+1)log5
3xlog7 - 5log7 = 4xlog5 + log5
3xlog7 - 4xlog5 = 5log7 + log5
x(3log7 - 4log5) = 5log7 + log5
x = (5log7 + log5) / (3log7 - 4log5)
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