Question 36422: simplify: (x^2-6x+8)/(x^2+3x-28) *(x^2+6x-7)/(x^2-3x+2) Found 2 solutions by ilana, vidhyak:Answer by ilana(307) (Show Source):
You can put this solution on YOUR website! Oh, I love when this happens!! It equals 1!
You factor each polynomial. (x^2-6x+8)=(x-2)(x-4), (x^2+6x-7)=(x+1)(x-1), (x^2+3x-28)=(x+7)(x-4), (x^2-3x+2)=(x-2)(x-1). so, the numerator and denominator all have the same terms, and they all cancel out.
You can put this solution on YOUR website! (x^2-6x+8)/(x^2+3x-28) *(x^2+6x-7)/(x^2-3x+2)
(x^2-6x+8) can be written as (x-4)(x-2)
(x^2+3x-28) can be written as (x+7)(x-4)
(x^2+6x-7) can be written as (x+7)(x-1)
(x^2-3x+2) can be written as (x-2)(x-1)
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