SOLUTION: An urn contains 15 balls identical in every respect except
color. There are 4 red balls, 8 green balls, and 3 blue balls.
(a) You draw two balls from the urn but replace the fir
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-> SOLUTION: An urn contains 15 balls identical in every respect except
color. There are 4 red balls, 8 green balls, and 3 blue balls.
(a) You draw two balls from the urn but replace the fir
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Question 364123: An urn contains 15 balls identical in every respect except
color. There are 4 red balls, 8 green balls, and 3 blue balls.
(a) You draw two balls from the urn but replace the first
ball before drawing the second. Find the probability
that the first ball is red and the second is green.
(b) Repeat part (a) but do not replace the first ball before
drawing the second
Hi,
15 balls f which 4 are red, 8 are green, and 3 are blue
With replacement of the first ball
P(first ball is red and the second is green) = 4/15 * 8/15 = 32/225= .142
without replacement (14 total balls in the urn on the second draw)
P(first ball is red and the second is green) = 4/15 * 8/14 = 32/210 = .152
