SOLUTION: A movie theater had a certain number of tickets to give away. Five people got the tickets. The first got one-third of the tickets, the second got one-fourth of the tickets, and th

Algebra ->  Inequalities -> SOLUTION: A movie theater had a certain number of tickets to give away. Five people got the tickets. The first got one-third of the tickets, the second got one-fourth of the tickets, and th      Log On


   

Question 364122: A movie theater had a certain number of tickets to give away. Five people got the tickets. The first got one-third of the tickets, the second got one-fourth of the tickets, and the third got one-fifth of the tickets. The fourth person got eight tickets, and there were five tickets left for the fifth person. Find the total number of tickets given away.
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
(x/3) + (x/4) + (x/5) + 8 + 5 = x

multiplying by 60 (LCD) ___ 20x + 15x + 12x + 480 + 300 = 60x