SOLUTION: the curve of a parabola passes through points (0,-4), (2,8) and (-2,0).Given that the axis of the parabola is parallel to y-axis.find the general equation of the parabola?.

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: the curve of a parabola passes through points (0,-4), (2,8) and (-2,0).Given that the axis of the parabola is parallel to y-axis.find the general equation of the parabola?.       Log On


   



Question 364090: the curve of a parabola passes through points (0,-4), (2,8) and (-2,0).Given that the axis of the parabola is parallel to y-axis.find the general equation of the parabola?.

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!

Hi
*Note: stand form for the equation of a parabola:
y = ax^2 + bx + c
Pt(0,4)tells us c = -4
y = ax^2 + bx - 4
(2,8) and -2,0)
8 = 4a + 2b - 4
0 = 4a - 2b - 4
8 = 8a - 8
16 = 8a
a = 2
b = 2 (8 = 8 + 2b - 4 )
Y= 2x^2 + 2x - 4
graph%28+300%2C+300%2C-15%2C15%2C-15%2C15%2C+2x%5E2%2B2x-4%29+