SOLUTION: how can i solve this? I'm confused! the sum of the degree measures of the three angles of a triangle is 180. Find the degree of the measures of the third angle given the degree

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Question 363961: how can i solve this? I'm confused!
the sum of the degree measures of the three angles of a triangle is 180. Find the degree of the measures of the third angle given the degree measure of the two angles.
a. 7x^2 + 6x + 45; 5x^2 + 10x - 55
b. 3x^3 - 15x^2 - 24x + 5; 9x^2 + 30x + 36
c. 9x^4 + 58x^3 + 24x^2 - 45x + 15; 11x^4 - 47x^3 + 16x^2 - 94x + 27
Answer by Alan3354(69443) About Me  (Show Source):
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the sum of the degree measures of the three angles of a triangle is 180. Find the degree of the measures of the third angle given the degree measure of the two angles.
a. 7x^2 + 6x + 45; 5x^2 + 10x - 55
1 angle is 7x^2 + 6x + 45 degrees.
The 2nd angle is 5x^2 + 10x - 55
Add those
= 12x^2 + 16x - 10 degrees
The 3rd angle is 180 - the sum
Angle 3 = 180 - (12x^2 + 16x - 10) degrees
= 190 - 12x^2 - 16x degrees
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Do the others the same way.
b. 3x^3 - 15x^2 - 24x + 5; 9x^2 + 30x + 36
c. 9x^4 + 58x^3 + 24x^2 - 45x + 15; 11x^4 - 47x^3 + 16x^2 - 94x + 27