SOLUTION: 1.A die is rolled and a card is selected from a standard 52 card deck. What is the probability of rolling a 3 and selecting a red card? 2. Jim rolls two dice. Let the sum of the

Algebra ->  Probability-and-statistics -> SOLUTION: 1.A die is rolled and a card is selected from a standard 52 card deck. What is the probability of rolling a 3 and selecting a red card? 2. Jim rolls two dice. Let the sum of the      Log On


   

Question 363925: 1.A die is rolled and a card is selected from a standard 52 card deck. What is the probability of rolling a 3 and selecting a red card?
2. Jim rolls two dice. Let the sum of the dice be the value of the first die added to the value of the second die. Find the probability of Jim rolling a sum greater than 8.
3. Two cards are drawn from a standart deck of 52 cards without replacement. Find the probability that both cards drawn are: Aces, Red Aces.
4. If four fair dice are rolled, what is the probability that each of the four numbers that appear will be different?
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
1.A die is rolled and a card is selected from a standard 52 card deck. What is the probability of rolling a 3 and selecting a red card? I'm assuming that you are rolling a fair 6-sided die. Then the prob'y %281%2F6%29%2A%2826%2F52+%29+=+1%2F12.
2. Jim rolls two dice. Let the sum of the dice be the value of the first die added to the value of the second die. Find the probability of Jim rolling a sum greater than 8. There are 4 possibilities for a sum of 9, 3 for 10, 2 for 11, and 1 for 12. Thus the probability is 10/36, or 5/18.
3. Two cards are drawn from a standard deck of 52 cards without replacement. Find the probability that both cards drawn are: Aces, Red Aces. For aces, probability is %284%2F52%29%2A%283%2F51%29+=+1%2F221. For both red aces, probability is %282%2F52%29%2A%281%2F51%29+=+1%2F1326.
4. If four fair dice are rolled, what is the probability that each of the four numbers that appear will be different? Probability is %286%2A5%2A4%2A3%29%2F%286%2A6%2A6%2A6%29+=+5%2F18.