SOLUTION: The area of a triangular section of a store cannot be more than 910 sq. ft. If the height of the triangular section is 52 feet, what should the base be?

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Question 363889: The area of a triangular section of a store cannot be more than 910 sq. ft. If the height of the triangular section is 52 feet, what should the base be?

Found 2 solutions by stanbon, ewatrrr:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
The area of a triangular section of a store cannot be more than 910 sq. ft. If the height of the triangular section is 52 feet, what should the base be?
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A = (1/2)base*height
910 = (1/2)(base*52)
26*base = 910
base = 35 ft.
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Cheers,
Stan H.

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi, 

*Note: Area of a triangular shape is = (1/2)b*h

Let b represent the base of this triangular shaped section of a store

question states

(1/2)52ft*b = 910ft^2

b = 35 ft