Question 363792: The perimeter of a rectangle is 64cm. Twice the width is 4cm more than the length. Find the dimensions of the rectangle Answer by vasumathi(46) (Show Source):
You can put this solution on YOUR website! twice the width is 4 cm more than the length
so...
2w = l+4 (where w is the width and l is the length)
the perimetre = 64 cms
perimetre in terms of w and l is p = 2l + 2w
so..
64 = 2l + l+4
64 = 3l+4
subtract 4 on both sides
64-4 = 3l +4 -4
60=3l
divide both sides by 3
60/3 = 3l/3
20 = l
so the length is 20 cms
we have 2w = l+4
2w = 20+4
2w = 24
so w = 24/2 = 12
so width = 12 cms
so the length = 20 cms
and width = 12 cms
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