SOLUTION: A gardener is making a planting in the shape of a trapezoid. It will have 35 plants in the front row, 31 in the second row, 27 in the third row and so on. If the pattern is consist
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Question 363770: A gardener is making a planting in the shape of a trapezoid. It will have 35 plants in the front row, 31 in the second row, 27 in the third row and so on. If the pattern is consistent, how many plants will there be in the last row? How many plants are there altogether Answer by robertb(5830) (Show Source):
You can put this solution on YOUR website! The sequence is an arithmetic sequence with a1 = 35, d = -4. Then . We want an > 0. So 39 - 4n>0, or 39> 4n, or n = 9. So there are 9 rows. Then a9 = 39 - 4*9 = 39-36 = 3. Thus there are 3 plants in the last row. There plants all in all.
