SOLUTION: Find the absolute maximum and absolute minimum values of the function below. If an absolute maximum or minimum does not exist, enter NONE. f(x) = x^2 + 432/x on the open interval

Algebra ->  Absolute-value -> SOLUTION: Find the absolute maximum and absolute minimum values of the function below. If an absolute maximum or minimum does not exist, enter NONE. f(x) = x^2 + 432/x on the open interval       Log On


   

Question 363663: Find the absolute maximum and absolute minimum values of the function below. If an absolute maximum or minimum does not exist, enter NONE.
f(x) = x^2 + 432/x on the open interval (0,infinity )
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
f%28x%29=x%5E2%2B432%2Fx
df%2Fdx=2x-432%2Fx%5E2=0
2x=432%2Fx%5E2
x%5E3=216
x=root%283%2C216%29=6
.
.
.

.
.
.
Absolute min: x=6, y=6%5E2%2B432%2F6=36%2B72=108
Absolute max: Does not exist.