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Question 36364: find two consecutive even integers whose product is
288
Answer by kirubakaran(5)   (Show Source):
You can put this solution on YOUR website! find two consecutive even integers whose product is
288
let x and x+2 are the two even intergers
therefore, x (x+2) = 288 ( the product of two integers)
x^2 +2x =288
x^2+2x-288=0
x^2 + 18x -16x -288 =0
x (x+18)-16(x+18)=0
x =18 and x =16 are the the integers
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