SOLUTION: Let 2^a = 5 and 2^b = 9. Using exponent rules, solve the equation in terms of a and/or b.
5^x = 32
x =
I don't think logs are used in this equation, but I can't figure ou
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-> SOLUTION: Let 2^a = 5 and 2^b = 9. Using exponent rules, solve the equation in terms of a and/or b.
5^x = 32
x =
I don't think logs are used in this equation, but I can't figure ou
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Question 363596: Let 2^a = 5 and 2^b = 9. Using exponent rules, solve the equation in terms of a and/or b.
5^x = 32
x =
I don't think logs are used in this equation, but I can't figure out the operation. Thanks! Found 2 solutions by edjones, Alan3354:Answer by edjones(8007) (Show Source):
You can put this solution on YOUR website! Let 2^a = 5 and 2^b = 9.
Using exponent rules, solve the equation in terms of a and/or b.
Solve what equation? Is that 1 problem or 2? Or 3?
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Maybe you mean this.
2^a = 5
a*log(2) = log(5)
a = log(5)/log(2)
a =~ 2.3219
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2^b = 9
Do it the same way.
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5^x = 32
x*log(5) = log(32)
x = log(32)/log(5)
x =~ 2.1534
