Question 363467: Can someone please help me solve this problem?
(y+1)/(y+3) - (y-2)/(y-3) = (2)/(y+3)
Any help would be so appreciated!!! Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! (y+1)/(y+3) - (y-2)/(y-3) = (2)/(y+3)
(y+1)/(y+3) - (2)/(y+3)-(y-2)/(y-3)=0
first two terms have same denominator
(y+1-2)/(y+3)-(y-2)/(y-3)=0
(y-1)/(y+3)-(y-2)/(y-3)=0
LCM = (y+3)(y-3)
((y-1)(y-3)-(y-2)(y+3))/(y+3)(y-3)=0
(y^2-4y+3)-(y^2+y-6)/(y+3)(y-3)=0
(y^2-4y+3-y^2-y+6)=0
-5y+9=0
-5y=-9
y=9/5
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m.ananth@hotmail.ca
