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Question 363153: Hi Guys,
Stuck with this question any help would be appreicated.
i) An object is positioned at the origin of the xy axis, Two forces act upon it, the first has magnitude of 9N and acts in the direction of the y-axis, The second has magnitude 4N and acts in the direction of the negative x axis, Calculate the magnitude and direction of the resultant force R.
(ii) An object moves in the xy plane with a velocity of 15ms^-1 in a direction 36.87degrees above the positive x axis. Resolve this vlocityinto two components, one labelled X along the x-axis and the other labelled Y along the y-axis
Would appreciate any help
Many Thanks
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! i) An object is positioned at the origin of the xy axis, Two forces act upon it, the first has magnitude of 9N and acts in the direction of the y-axis, The second has magnitude 4N and acts in the direction of the negative x axis, Calculate the magnitude and direction of the resultant force R.
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d = sqrt(9^2+4^2) = sqrt(97)
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direction invtan(9/-4) = 180-66.038 = 113.96 degrees
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(ii) An object moves in the xy plane with a velocity of 15ms^-1 in a direction 36.87degrees above the positive x axis. Resolve this velocity into two components, one labeled X along the x-axis and the other labeled Y along the y-axis
x = 15*cos(36.87) = 12
y = 15*sin(36.87) = 9
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Cheers,
Stan H.
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