SOLUTION: Find the area of the triangle with vertices of A(0, 0), B(3, 4), and C(4, 3).

Algebra ->  Triangles -> SOLUTION: Find the area of the triangle with vertices of A(0, 0), B(3, 4), and C(4, 3).      Log On


   

Question 363088: Find the area of the triangle with vertices of A(0, 0), B(3, 4), and C(4, 3).
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
3.5 sq units
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Arrange the points like this:
0 3 4 0
0 4 3 0
(The 1st point is repeated)
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Add the diagonal products from lower left to upper right:
0 + 16 + 0 = 16
Add the diagonal products from upper left to lower right:
0 + 9 + 0 = 9
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Get the absolute value of the difference:
|9 - 16| = 7
Area = 7/2 = 3.5 sq units
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This works for any # of points, any shape.