Hi,
6y+5x=-18
solving for y to generate the slope-intercept form y = mx + b
y = -(5/6)x - 3 negative slope, line slants to the left
Line crosses the y axis when y has a value of -3. Pt(0,-3) the y intercept
slope verifies (-6,2) is a point on the line. (y increasing by 5, x decreasing by 6)