SOLUTION: Hello, Can someone please check my work. Essay; show all work. A simple dartboard has three areas� the main board has a radius of 10 inches, there is a circle with a radius of 5

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Question 363074: Hello, Can someone please check my work.
Essay; show all work. A simple dartboard has three areas� the main board has a radius of 10 inches, there is a circle with a radius of 5 inches, and the bullseye has a radius of 2 inches. What is the probability of a random dart landing inside the bullseye. Here is my Answer:
Find the Area of Bull�s-eye
A = pi *r^2 Start with the area of a circle formula.
A = pi*(2)^2 we plug in r=2
A = 3.14159*(2)^2 we replace pi with 3.14159 ( since pi is approximately 3.14159
A = 3.14159*(4) we square 2 to get 4
A=12.56636 we multiply 3.14159 and 4 to get 12.56636
So the area of the bull�s-eye with a radius of 2 units is roughly 12.56636 square units, the nearest thousandth.
Area of a whole board

A = pi * r^2 Start with the area of a circle formula.
A = pi * (15)^2 we plug in r=15
A = 3.14159*(15)^2 We replace pi with 3.14159 (since pi is approximately 3.14159)
A = 3.14159*(225) Square 15 to get 225.
A=706.85775 Multiply 3.14159 and 225 to get 706.85775
So the area of the circle with a radius of 15units is roughly 706.85775 square units.
CHANCE FOR A BULL'S EYE. 12.56636/706.85775 =0.017778 square units

Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website!
No, your methodology is correct, however the radius of the entire board is not .