SOLUTION: (16k^4m^-8)^1/3

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Question 362945: (16k^4m^-8)^1/3
Answer by HasanSahin(52) About Me  (Show Source):
You can put this solution on YOUR website!
+%2816%2Ak%5E%284%2Am%29%5E-8%29%5E%281%2F3%29+ = +%2816%2Ak%5E%28-32%2Am%29%29%5E%281%2F3%29+ = +%28%282%5E4%29%2Ak%5E%28-32%2Am%29%29%5E%281%2F3%29+ = +%28%282%5E%28-128%2Am%29%29%2Ak%5E%28-32%2Am%29%29%5E%281%2F3%29+ = +2%5E%28-42.667%2Am%29%2Ak%5E%28-10.667%2Am%29+
Moreover,I'll post an answer of another question in order to explain you more about exponential numbers..
Observe..
If 7^-x= 1/4, what does 49x equal?

+7%5E%28-x%29+=+1%2F4+ and you want to solve +49%5Ex+ where we can write it as +7%5E2%5Ex+ and also as+7%5Ex%5E2+ and also as+7%5E%28-x%29%5E%28-2%29+
If you give a name to +7%5E%28-x%29+ as "a"
We'll have +a%5E%28-2%29+
If +a+=+1%2F4+ >> so +%281%2F4%29%5E%28-2%29+ equals to +-1%2F16+
RF.