SOLUTION: Good evening! I'm having trouble finding the zeros for f(t) = t^5 -6t^3 + 9t I tried factoring: = t(t^4 - 6t^2 + 9) = t(t^2 -3)^2 t = 0 (t^2 - 3)^2 = 0 sqrt of bot

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Good evening! I'm having trouble finding the zeros for f(t) = t^5 -6t^3 + 9t I tried factoring: = t(t^4 - 6t^2 + 9) = t(t^2 -3)^2 t = 0 (t^2 - 3)^2 = 0 sqrt of bot      Log On


   

Question 362913: Good evening!
I'm having trouble finding the zeros for f(t) = t^5 -6t^3 + 9t
I tried factoring:
= t(t^4 - 6t^2 + 9)
= t(t^2 -3)^2
t = 0
(t^2 - 3)^2 = 0
sqrt of both sides (can i do that?)
t^2 - 3 = 0
t = +/- sqrt(3)
This definitely doesn't look right but I'm not sure how else to solve this. Any help you can provide is great appreciated! Thanks for your time :)
Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!
You did just fine:

The zeros are 0 and %22%22+%2B-+sqrt%283%29

The graph is 

graph%28240%2C400%2C-3%2C3%2C-5%2C5%2Cx%5E5-6x%5E3+%2B+9x%29

You can see it has double zeros at %22%22+%2B-+sqrt%283%29, about ±1.7,
and a single zero at 0.

Edwin