Question 36287: the larger of two consecutive integers is 7 greater than twice the smaller. find the integers. make and solve an equation Found 2 solutions by checkley71, vidhyak:Answer by checkley71(8403) (Show Source):
You can put this solution on YOUR website! X & X+1 ARE THE TWO CONSECUTIVE INTERGERS THEN THE INTEGERS ARE X+1=2X+7
OR -X=6 OR X=-6 OR THE TWO CONSECUTIVE DIGITS ARE (-6 & -5) OR -6+1=2*-6+7 OR -5=-12+7 OR -5=-5
You can put this solution on YOUR website! The larger of two consecutive integers is 7 greater than twice the smaller. find the integers. make and solve an equation
Let the smallest integer be x
Since the numbers are 2 consecutive integers, let the largest integer be x+1
The larger of two integers is 7 greater than twice the smaller.
The equation is
x + 1 = 2x + 7
x - 2x = 7 - 1
-x = 6
x = -6
Since x is the smallest integer, - 6 is the smallest integer
Since x+1 is the largest integer, - 6+1 = -5 is the largest integer
we can verify the answer
The larger of two integers is 7 greater than twice the smaller.
-5 = 2(-6)+7
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