SOLUTION: It is estimated that 60% of all college graduates find a job in their chosen career field within one year of graduation. If six college graduates from the year 2009 are chosen at

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Question 362835: It is estimated that 60% of all college graduates find a job in their chosen career field within one year of graduation. If six college graduates from the year 2009 are chosen at random, let x be the number who found a job within one year.
I have calculated the probabilities as follow: P(0) .004, P(1) .037, P(2) .138, P(3) .276, P(4) .311 P(5) .187 P(6) .047
a) what is the probability that fewer than 4 found a job in their field? I think it is .455
b) what is the probability that all of them found a job in their field? I think it is 1
c) Compute the mean, the expected number of job seekers (round to the appropriate whole number) I think it is 4 people
d) Compute the standard deviation of the number of successful job seekers. I think it is either 1.2 or 1.27
Any help with the doublechecks would be great. Thanks!

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
It is estimated that 60% of all college graduates find a job in their chosen career field within one year of graduation. If six college graduates from the year 2009 are chosen at random, let x be the number who found a job within one year.
I have calculated the probabilities as follow: P(0) .004, P(1) .037, P(2) .138, P(3) .276, P(4) .311 P(5) .187 P(6) .047
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Binomial Problem with n=6 and p = 0.6

a) what is the probability that fewer than 4 found a job in their field? I think it is .455
OK
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b) what is the probability that all of them found a job in their field? I think it is 1
No.
P(x=6) = 0.06^6 = 0.04666 as you listed above.
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c) Compute the mean, the expected number of job seekers (round to the appropriate whole number) I think it is 4 people
mean of binomial = np = 6*0.6 = 3.6
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d) Compute the standard deviation of the number of successful job seekers. I think it is either 1.2 or 1.27
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std of binomial is sqrt(npq) = sqrt(6*0.6*0.4)= 1.2
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Cheers,
Stan H.