Question 362599: A horse and two cows together cost $680. Find the cost of a cow and a horse, if a horse cost $80 more than a cow. Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! H=C+80
H+2C=680
(C+80)+2C=680
C+80+2C=680
3C=680-80
3C=600
C=600/3
C=$200 COST OF ONE COW.
H=2*200+80=400+80=$480 COST OF ONE HORSE.
PROOF:
480+200=680
680=680