SOLUTION: a)log(base 6) 6^9 b)1n e^-3x. I think the answer to this is -3x am I correct Thank you for all of you help.

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: a)log(base 6) 6^9 b)1n e^-3x. I think the answer to this is -3x am I correct Thank you for all of you help.      Log On


   

Question 362520: a)log(base 6) 6^9
b)1n e^-3x. I think the answer to this is -3x am I correct
Thank you for all of you help.
Found 2 solutions by jim_thompson5910, josmiceli:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Remember that log%28b%2C%28b%5Ex%29%29=x and that b%5E%28log%28b%2Cx%29%29=x

a) Let b=6 and x=9 to get log%286%2C%286%5E9%29%29=9

b) Let b=e and replace x with -3x to get ln%28e%5E%28-3x%29%29=-3x

Note: ln is the natural log (ie the log with base 'e').

Answer by josmiceli(19441) About Me  (Show Source):