SOLUTION: express the logarithm in terms of log2 M and log2 N: log2 cube root of M^2N

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Question 36249: express the logarithm in terms of log2 M and log2 N: log2 cube root of M^2N
Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
log_2 (cbrt (M^2N)) =
(1/3)*(log_2 (M^2N)) =
(1/3)*(log_2 M^2 + log_2 N) =
(1/3)*(2*log_2 M + log_2 N) =
(2/3)*log_2 M + (1/3)*log_2 N