SOLUTION: Find the polynomial P(x) having real coefficients, with the degree and zeroes indicate. Assume that lead coefficient is 1. Recall (a+bi)(a-bi)=a2+b2 (the last one is read a squar

Algebra ->  Coordinate-system -> SOLUTION: Find the polynomial P(x) having real coefficients, with the degree and zeroes indicate. Assume that lead coefficient is 1. Recall (a+bi)(a-bi)=a2+b2 (the last one is read a squar      Log On


   



Question 362448: Find the polynomial P(x) having real coefficients, with the degree and zeroes indicate. Assume that lead coefficient is 1. Recall (a+bi)(a-bi)=a2+b2 (the last one is read a squared + b squared).
degree4, x=-1, x=1+2i.

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Since x=1%2B2i is a zero so is x=1-2i since complex solutions only come in complex conjugate pairs.
However since the degree is 4, without additional information on the other real root, you can't determine the polynomial.
Just for illustration assume the fourth root is x=a.
.
.
f%28x%29=%28x%2B1%29%28x-a%29%28x-%281%2B2i%29%29%28x-%281-2i%29%29
f%28x%29=%28x%2B1%29%28x-a%29%28x%5E2-2x%2B5%29
f%28x%29=%28x%5E2%2B%281-a%29x-a%29%28x%5E2-2x%2B5%29
highlight%28f%28x%29=x%5E4-%28a%2B1%29x%5E3%2B%28a%2B3%29x%5E2-%283a-5%29x-5a%29