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Question 362442: A man wanted to get into his work building, but he had forgotten his Code. However, he did remember five clues. These are what those clues were:
The fifth number plus the third number equals fourteen.
The fourth number is one more than the second number.
The first number is one less than twice the second number.
The second number plus the third number equals ten.
The sum of all five numbers is 30.
What were the five numbers and in what order?
Answer by Edwin McCravy(20059)   (Show Source):
You can put this solution on YOUR website! A man wanted to get into his work building, but he had forgotten his Code. However, he did remember five clues. These are what those clues were:
Let A = 1st number.
Let B = 2nd number.
Let C = 3rd number.
Let D = 4th number.
Let E = 5th number.
The fifth number plus the third number equals fourteen.
E + C = 14
The fourth number is one more than the second number.
D = B + 1
The first number is one less than twice the second number.
A = 2B - 1
The second number plus the third number equals ten.
B + C = 10
The sum of all five numbers is 30.
A + B + C + D + E = 30
What were the five numbers and in what order?
(1) E + C = 14
(2) D = B + 1
(3) A = 2B - 1
(4) B + C = 10
(5) A + B + C + D + E = 30
Write the equations up so that corresponding
terms line up vertically
(1) C + E = 14
(2) -B + D = 1
(3) A - 2B = -1
(4) B + C = 10
(5) A + B + C + D + E = 30
Can you solve that system? If not ask me how to.
A=7, B=4, C=6, D=5, E=8
Edwin
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