SOLUTION: express the logarithm in terms of log2 M and log2 N: log2 cube root of M^2N

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Question 36234: express the logarithm in terms of log2 M and log2 N: log2 cube root of M^2N
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
log2 cube root of M^2N
Notice 1st that you are taking the cube root.
Write (1/3)log2(m^2n)
Notice next that you are taking the log of a product.
Write (1/3)[logm^2 + logn]
Then notice that the "m" is squared.
Write (1/3)[2log m + log n]
Simplify as follows:
(2/3)log m + (1/3)log n
Cheers,
Stan H.