SOLUTION: please help me with this equation:{{{Ln(x+3)+Lnx=Ln4}}}

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Question 36216: please help me with this equation:Ln%28x%2B3%29%2BLnx=Ln4
Answer by Prithwis(166) About Me  (Show Source):
You can put this solution on YOUR website!
Ln(x+3)+Lnx=Ln4
=> Ln[x(x+3)] = Ln 4
=> x(x+3) = 4
=> x^2+3x-4 = 0
=> (x+4)(x-1) = 0
=> x=-4 or x = 1
x cannot be -4 because Ln of negative is not possible.
So, x = 1