SOLUTION: How many ounces of 35% solution of sulfuric acid(and distilled water) must be mixed with 12 ounces of a 20% solution to get a 30% solution of sulfuric acid?

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Question 362137: How many ounces of 35% solution of sulfuric acid(and distilled water) must be mixed with 12 ounces of a 20% solution to get a 30% solution of sulfuric acid?
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
.35x+.20*20=.30(20+x)
.35x+4=6+.30x
.35x-.30x=6-4
.05x=2
x=2/.05
x=40 ounces of 35% solution is used.
Proof:
.35*40+.20*20=.30(20+40)
14+4=.30*60
18=18