SOLUTION: Ok another question solve (w-5)^2-27=0 where w is a real number

Algebra ->  Real-numbers -> SOLUTION: Ok another question solve (w-5)^2-27=0 where w is a real number      Log On


   



Question 36202: Ok another question
solve (w-5)^2-27=0 where w is a real number

Found 2 solutions by Prithwis, longjonsilver:
Answer by Prithwis(166) About Me  (Show Source):
You can put this solution on YOUR website!
(w-5)^2-27=0 => (w-5) = sqrt(27) or (w-5) = -sqrt(27)
=> w = 5+3sqrt(3) or w = 5-3sqrt(3)

Answer by longjonsilver(2297) About Me  (Show Source):
You can put this solution on YOUR website!
+%28w-5%29%5E2-27=0+
+%28w-5%29%5E2+=+27+
+%28w-5%29+=+sqrt%2827%29+ or +%28w-5%29+=+-+sqrt%2827%29+
+w+=+5+%2B+sqrt%2827%29+ or +w+=+5+-+sqrt%2827%29+
+w+=+5+%2B+sqrt%289%2A3%29+ or +w+=+5+-+sqrt%289%2A3%29+
+w+=+5+%2B+sqrt%289%29sqrt%283%29+ or +w+=+5+-+sqrt%289%29sqrt%283%29+
+w+=+5+%2B+3sqrt%283%29+ or +w+=+5+-+3sqrt%283%29+

jon