SOLUTION: Hi, I really need help with this question. Please help me! I would be really thankful 2. Two cars are moving in the same direction pass a point on the road at the same time. Ca

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Question 361881: Hi, I really need help with this question. Please help me! I would be really thankful
2. Two cars are moving in the same direction pass a point on the road at the same time. Car A is moving with a constant velocity of 15m/s. Car B has a velocity of 5m/s at that instant and is accelerating at the rate of 1m/s^2.
a) Useing the formula s=ut+1/2at^2 where s is the distance from the starting point in metres, u is the velocity initially, a is acceleration in m/s^2 and t is the time in seconds. write a relationship between s and t for car A and car B.
b) Sketch both functions on the same axes, placing s on the vertical and t on the horizontal.
c) calculate the value of t which satisfies both of these equations.
d) what does this value of t mean in relation to the position of the two cars relative to each other?
It would be great if you could figure these questions out for me and explain them. Thanks.
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Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website!
Two cars are moving in the same direction pass a point on the road at the same time. Car A is moving with a constant velocity of 15m/s. Car B has a velocity of 5m/s at that instant and is accelerating at the rate of 1m/s^2.
a) Useing the formula s=ut+1/2at^2 where s is the distance from the starting point in metres, u is the velocity initially, a is acceleration in m/s^2 and t is the time in seconds. write a relationship between s and t for car A and car B.
b) Sketch both functions on the same axes, placing s on the vertical and t on the horizontal.
c) calculate the value of t which satisfies both of these equations.
d) what does this value of t mean in relation to the position of the two cars relative to each other?
It would be great if you could figure these questions out for me and explain them. Thanks.
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Car A it travels distance s1 .
function = s1=ut+1/at^2
s1=15t+0 (no acceleration)
s1=15t
...
Car B initial velocity = 5m/s
s2=5t+1/2*1*t^2 ( a=1m/s)
s2=5t+t^2/2
..
..
15t=5t+t^2/2
multiply by2
30t=10t+t^2
t^2+10t-30t=0
t^2-20t=0
t^2=20t
t=20 the Car B overtakes car A at a distance of 300 miles.

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m.ananth@hotmail.ca