SOLUTION: how do you solve this problem : 2e and then in the exponent log base 3 (x +2) = 14?

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Question 36187: how do you solve this problem : 2e and then in the exponent log base 3 (x +2) = 14?
Answer by astromathman(21) About Me  (Show Source):
You can put this solution on YOUR website!
2e%5E%283%28x%2B2%29%29+=+14. Take ln of both sides, remembering that ln%28ab%29=ln%28a%29%2Bln%28b%29: ln2%2Bln%28e%5E%283%28x%2B2%29%29%29=ln14, then, remembering that ln%28x%29 and e%5Ex are inverse functions, ln2%2B3%28x%2B2%29=ln14. From here just treat it as an ordinary Alg I equation and solve for x, keeping in mind that ln2 and ln14 are simply two numbers.
Solution:
x=%28ln14-ln2%29%2F3-2