SOLUTION: Billy has 5 coins, 1 penny, 1 nickel, 1 dime, 1 quarter, and 1 half-dollar. How many different sums of money can Billy form by using 1, 2, or 3 of these coins?

Algebra ->  Probability-and-statistics -> SOLUTION: Billy has 5 coins, 1 penny, 1 nickel, 1 dime, 1 quarter, and 1 half-dollar. How many different sums of money can Billy form by using 1, 2, or 3 of these coins?      Log On


   

Question 361724: Billy has 5 coins, 1 penny, 1 nickel, 1 dime, 1 quarter, and 1 half-dollar. How many different sums of money can Billy form by using 1, 2, or 3 of these coins?
Found 2 solutions by solver91311, edjones:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


You need:

which is the number of combinations of things taken at a time and is calculated by

Specifically: . You get to do your own arithmetic.

John

My calculator said it, I believe it, that settles it
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Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
1) 5
.
2) 5C1*4C1=20
.
3) 5C1*4C2*3C1=60
.
Ed