SOLUTION: Suppose that 51% of the women who gave birth at a certain hospital last year were over years 30 old, and that 51% were unmarried. If 61% of the women were over30 or unmarried (or

Algebra ->  Probability-and-statistics -> SOLUTION: Suppose that 51% of the women who gave birth at a certain hospital last year were over years 30 old, and that 51% were unmarried. If 61% of the women were over30 or unmarried (or       Log On


   



Question 361498: Suppose that 51% of the women who gave birth at a certain hospital last year were over years 30 old, and that 51% were unmarried. If 61% of the women were over30 or unmarried (or both), what is the probability that a woman who gave birth at the hospital was both unmarried and over 30 ?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Suppose that 51% of the women who gave birth at a certain hospital last year were over years 30 old,
and that 51% were unmarried.
If 61% of the women were over 30 or unmarried (or both), what is the probability that a woman who gave birth at the hospital was both unmarried and over 30 ?
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P(>30 and unmarried) = P(>30) + P(unmarried) - P(>30 or unmarried)
= 0.51 + 0.51 - 0.61
= 0.41
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Cheers,
Stan H.