SOLUTION: find the dimension of a rectangle whose lenght is three cm less than twice its width, with a perimeter of 33 cm

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Question 360902: find the dimension of a rectangle whose lenght is three cm less than twice its width, with a perimeter of 33 cm
Answer by IWork4Dessert(60) About Me  (Show Source):
You can put this solution on YOUR website!
Let width=x and length=2x-3. There are two widths in every rectangle and two lengths in every rectangle. So:
2x + 2(2x - 3) = 33
2x + 4x - 6 =33
6x - 6 = 33
6x = 27
x = 4.5
If you need me to break it down further, I will.
~IW4D